4x^2=223

Solution for 4x^2=223 equation:

4x^2=223

We move all terms to the left:

4x^2-(223)=0

a = 4; b = 0; c = -223;
Δ = b2-4ac
Δ = 02-4·4·(-223)
Δ = 3568
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3568}=\sqrt{16*223}=\sqrt{16}*\sqrt{223}=4\sqrt{223}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{223}}{2*4}=\frac{0-4\sqrt{223}}{8}
=-\frac{4\sqrt{223}}{8}
=-\frac{\sqrt{223}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{223}}{2*4}=\frac{0+4\sqrt{223}}{8}
=\frac{4\sqrt{223}}{8}
=\frac{\sqrt{223}}{2}
$